Vertical component of velocity = \( 20 \sin 45^\circ = 20 \times \frac\sqrt22 = 10\sqrt2 \) - AMAZONAWS

Understanding Vertical Component of Velocity: A Clear Explanation with \( 20 \sin 45^\circ = 10\sqrt{2} \)

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$Vertical component of velocity = \( 20 \sin 45^\circ = 20 \times \frac{\sqrt{2}}{2} = 10\sqrt{2} \)$