Maximum height = $ \frac(10\sqrt2)^22 \times 9.8 = \frac20019.6 \approx 10.2 \, \textmeters $ - AMAZONAWS

Maximum Height of a Projectile: Calculating the Peak Ã¢ÂÂ A Detailed Explanation

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$Maximum height = $ \frac{(10\sqrt{2})^2}{2 \times 9.8} = \frac{200}{19.6} \approx 10.2 \, \text{meters} $$