\sum_k=1^50 \frac1k(k+2) = \frac12 \sum_k=1^50 \left( \frac1k - \frac1k+2 \right) - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$\sum_{k=1}^{50} \frac{1}{k(k+2)} = \frac{1}{2} \sum_{k=1}^{50} \left( \frac{1}{k} - \frac{1}{k+2} \right)$