\cos(2lpha - 90^\circ) = \cos(90^\circ - 2lpha) = \sin(2lpha) \quad ext(since \cos(90^\circ - x) = \sin x ext). - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$\cos(2lpha - 90^\circ) = \cos(90^\circ - 2lpha) = \sin(2lpha) \quad ext{(since } \cos(90^\circ - x) = \sin x ext{)}.$