\sum_n=1^50 \frac1n(n+2) = \frac12 \sum_n=1^50 \left( \frac1n - \frac1n+2 \right). - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$\sum_{n=1}^{50} \frac{1}{n(n+2)} = \frac{1}{2} \sum_{n=1}^{50} \left( \frac{1}{n} - \frac{1}{n+2} \right).$