We are given that $ \fracdVdt = k \sin \theta $, and $ \theta = 60^\circ $, so $ \sin \theta = \frac\sqrt32 $. Substituting: - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$We are given that $ \frac{dV}{dt} = k \sin \theta $, and $ \theta = 60^\circ $, so $ \sin \theta = \frac{\sqrt{3}}{2} $. Substituting:$