\sum_k=1^10 k^3 = \left( \frac10 \times 112 \right)^2 = (55)^2 = 3025 - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$\sum_{k=1}^{10} k^3 = \left( \frac{10 \times 11}{2} \right)^2 = (55)^2 = 3025$