Solution: Start with $a_1 = 1$. Compute $a_2 = M(a_1) = 1 - rac1^22 = rac12$. Next, compute $a_3 = M(a_2) = rac12 - rac(rac12)^22 = rac12 - rac18 = rac38$. Thus, the value of $a_3$ is $oxed\dfrac38$. - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$Solution: Start with $a_1 = 1$. Compute $a_2 = M(a_1) = 1 - rac{1^2}{2} = rac{1}{2}$. Next, compute $a_3 = M(a_2) = rac{1}{2} - rac{( rac{1}{2})^2}{2} = rac{1}{2} - rac{1}{8} = rac{3}{8}$. Thus, the value of $a_3$ is $oxed{\dfrac{3}{8}}$.$