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Home » So \( raca + ba - b = rac3 \pm \sqrt52 \). Let’s take one root (both valid due to symmetry). Set: - AMAZONAWS

So \( raca + ba - b = rac3 \pm \sqrt52 \). Let’s take one root (both valid due to symmetry). Set: - AMAZONAWS

📅 March 6, 2026 👤 scraface
Mar 06, 2026
So \( rac{a + b}{a - b} = rac{3 \pm \sqrt{5}}{2} \). Let’s take one root (both valid due to symmetry). Set:

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