Let $d$ be a positive divisor of 100. Then $x = d$ and $y = \frac100d$ is an integer. Since $xy = 100$, both $(d, 100/d)$ and $(-d, -100/d)$ are solutions. - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$Let $d$ be a positive divisor of 100. Then $x = d$ and $y = \frac{100}{d}$ is an integer. Since $xy = 100$, both $(d, 100/d)$ and $(-d, -100/d)$ are solutions.$

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