ight) \), for $ t > 0 $, $ f(t) < t $ when $ 1 - ract^26 < 1 $, which is always true, but more importantly, for $ t \in (0, \sqrt6) $, $ c_n+1 = f(c_n) < c_n $. With $ c_1 = 0.5 $, compute: - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$ight) \), for $ t > 0 $, $ f(t) < t $ when $ 1 - rac{t^2}{6} < 1 $, which is always true, but more importantly, for $ t \in (0, \sqrt{6}) $, $ c_{n+1} = f(c_n) < c_n $. With $ c_1 = 0.5 $, compute:$

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