$f'(x) = 3 \times 3x^3-1 - 5 \times 2x^2-1 + 6 \times 1x^1-1 = 9x^2 - 10x + 6$. - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$$f'(x) = 3 \times 3x^{3-1} - 5 \times 2x^{2-1} + 6 \times 1x^{1-1} = 9x^2 - 10x + 6$.$