But $ v > 0 $, so $ u = \sqrtv > 0 $, thus $ u = 0 $ is invalid. Valid solutions: $ u = 2 \Rightarrow v = 4 $, $ u = 3 \Rightarrow v = 9 $ - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$But $ v > 0 $, so $ u = \sqrt{v} > 0 $, thus $ u = 0 $ is invalid. Valid solutions: $ u = 2 \Rightarrow v = 4 $, $ u = 3 \Rightarrow v = 9 $$