Both equations are identical. So, $ a^2 + bc = 1 $ holds. Thus, the conditions are $ d = -a $ and $ a^2 + bc = 1 $. - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$Both equations are identical. So, $ a^2 + bc = 1 $ holds. Thus, the conditions are $ d = -a $ and $ a^2 + bc = 1 $.$