\(x = \frac-b \pm \sqrtb^2 - 4ac2a\), where \(a = 4\), \(b = -50\), \(c = 40\). - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$\(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), where \(a = 4\), \(b = -50\), \(c = 40\).$