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Home » The cross-sectional area of the cylinder is \(\pi (3)^2 = 9\pi\). - AMAZONAWS

The cross-sectional area of the cylinder is \(\pi (3)^2 = 9\pi\). - AMAZONAWS

📅 March 6, 2026 👤 scraface
Mar 06, 2026
The cross-sectional area of the cylinder is \(\pi (3)^2 = 9\pi\).

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📌 Solution: Let the radius of the circular lake be $ r $ km. The chord length is 10 km, so half the chord length is $ 5 $ km. The perpendicular distance from the center to the chord is 3 km. By the Pythagorean Theorem applied to the right triangle formed by the radius, half the chord, and the perpendicular from the center to the chord, we have:
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📌 \boxed{\dfrac{14}{33}}
📌 \cdot 2 = 1440

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