\int_0^45 (60 - (X + 15))\, dX = \int_0^45 (45 - X)\, dX = \left[45X - \fracX^22\right]_0^45 = 45 \cdot 45 - \frac45^22 = 2025 - \frac20252 = \frac20252 - AMAZONAWS 📅 March 6, 2026 👤 scraface Mar 06, 2026
![\int_0^{45} (60 - (X + 15))\, dX = \int_0^{45} (45 - X)\, dX = \left[45X - \frac{X^2}{2}\right]_0^{45} = 45 \cdot 45 - \frac{45^2}{2} = 2025 - \frac{2025}{2} = \frac{2025}{2}](https://soloferat.biz.id/images/int045-60---x--15-dx--int045-45---x-dx--left45x---fracx22right045--45-cdot-45---frac4522--2025---frac20252--frac20252.jpg)
