But wait — no: $F_n+2$ gives the count for $k=1$ to $k=\lfloor (n+1)/2 \rfloor$, but we want exactly 4 H’s? No — the problem does not fix number of H’s. It allows any number, as long as no two are adjacent. - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$But wait — no: $F_{n+2}$ gives the count for $k=1$ to $k=\lfloor (n+1)/2 \rfloor$, but we want **exactly 4 H’s**? No — the problem does not fix number of H’s. It allows any number, as long as no two are adjacent.$

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