But $ a^2 - b^2 = (a - b)(a + b) $, and $ a^2 + b^2 = (a + b)^2 - 2ab $. Instead, observe $ S = rac2(a^2 + b^2)a^2 - b^2 $. Let $ a = 1 $, $ b = i $: - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$But $ a^2 - b^2 = (a - b)(a + b) $, and $ a^2 + b^2 = (a + b)^2 - 2ab $. Instead, observe $ S = rac{2(a^2 + b^2)}{a^2 - b^2} $. Let $ a = 1 $, $ b = i $:$

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