Try $ C(t) = \frac10(t/2 + 1) = \frac20t+2 $? Then $ C' = -20/(t+2)^2 $. Set = -5: $ (t+2)^2 = 4 \Rightarrow t = 2 $. - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$Try $ C(t) = \frac{10}{(t/2 + 1)} = \frac{20}{t+2} $? Then $ C' = -20/(t+2)^2 $. Set = -5: $ (t+2)^2 = 4 \Rightarrow t = 2 $.$