Set \( C(t) = \frac10(t+3) \). Then \( C' = -10/(t+3)^2 = -1 \Rightarrow (t+3)^2 = 10 \Rightarrow t \approx 1.16 — no. - AMAZONAWS 📅 March 6, 2026 👤 scraface Mar 06, 2026