Rate of change is $ C'(t) = \fracddt\left(10(t+2)^-1\right) = -10(t+2)^-2 $. - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$Rate of change is $ C'(t) = \frac{d}{dt}\left(10(t+2)^{-1}\right) = -10(t+2)^{-2} $.$