\fracdCdt = -10/(t+2)^2 = -1 \Rightarrow (t+2)^2 = 10 \Rightarrow t = \sqrt10 - 2 \approx 1.16 - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$\frac{dC}{dt} = -10/(t+2)^2 = -1 \Rightarrow (t+2)^2 = 10 \Rightarrow t = \sqrt{10} - 2 \approx 1.16$