Alternatively, perhaps the function is $ C(t) = 10e^-0.1t $, then $ C' = -1e^-0.1t $, set to -1: then $ e^-0.1t = 1 \Rightarrow t = 0 $. - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$Alternatively, perhaps the function is $ C(t) = 10e^{-0.1t} $, then $ C' = -1e^{-0.1t} $, set to -1: then $ e^{-0.1t} = 1 \Rightarrow t = 0 $.$