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Home » Since \(x^2 + y^2 + z^2 = 1\), we have: - AMAZONAWS

Since \(x^2 + y^2 + z^2 = 1\), we have: - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$Since \(x^2 + y^2 + z^2 = 1\), we have:$

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\[ c = 2 \]

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\(a^2 = 25\), \(b^2 = 0\) gives \((a, b) = (\pm 5, 0)\)
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