x^2 - 2x + y^2 + z^2 = 0 \implies (x^2 - 2x + 1) + y^2 + z^2 = 1 \implies (x - 1)^2 + y^2 + z^2 = 1. - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$x^2 - 2x + y^2 + z^2 = 0 \implies (x^2 - 2x + 1) + y^2 + z^2 = 1 \implies (x - 1)^2 + y^2 + z^2 = 1.$