Solution: Using De Moivre’s Theorem, $ (\cos \theta + i \sin \theta)^n = \cos(n\theta) + i \sin(n\theta) $. Here, $ n = 5 $, $ \theta = 72^\circ $: - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$Solution: Using De Moivre’s Theorem, $ (\cos \theta + i \sin \theta)^n = \cos(n\theta) + i \sin(n\theta) $. Here, $ n = 5 $, $ \theta = 72^\circ $:$