So ∫₁² (0.5)^u du = [ -u / ln(2) ]₁² = ( -2/ln2 ) - ( -1/ln2 ) = (-2 + 1)/ln2 = -1/ln2 - AMAZONAWS 📅 March 11, 2026 👤 scraface Mar 11, 2026
![So ∫₁² (0.5)^u du = [ -u / ln(2) ]₁² = ( -2/ln2 ) - ( -1/ln2 ) = (-2 + 1)/ln2 = -1/ln2](https://soloferat.biz.id/images/so--05u-du----u--ln2-----2ln2------1ln2----2--1ln2---1ln2.jpg)
