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Home » s^2 = \sin^2 x + \cos^2 x + 2\sin x \cos x = 1 + 2p \Rightarrow p = \fracs^2 - 12 - AMAZONAWS

s^2 = \sin^2 x + \cos^2 x + 2\sin x \cos x = 1 + 2p \Rightarrow p = \fracs^2 - 12 - AMAZONAWS

📅 March 11, 2026 👤 scraface
Mar 11, 2026
s^2 = \sin^2 x + \cos^2 x + 2\sin x \cos x = 1 + 2p \Rightarrow p = \frac{s^2 - 1}{2}

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