P(2) = \binom42 (0.3)^2 (0.7)^2 = 6 \cdot (0.09) \cdot (0.49) = 6 \cdot 0.0441 = 0.2646 - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$P(2) = \binom{4}{2} (0.3)^2 (0.7)^2 = 6 \cdot (0.09) \cdot (0.49) = 6 \cdot 0.0441 = 0.2646$