However, the condition $\mathbfv \cdot \mathbfa = 0$ implies $v_1 + 2v_2 + 3v_3 = 0$. Substituting $v_2 = 6 + 2v_1$ and $v_3 = 11 + 3v_1$: - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$However, the condition $\mathbf{v} \cdot \mathbf{a} = 0$ implies $v_1 + 2v_2 + 3v_3 = 0$. Substituting $v_2 = 6 + 2v_1$ and $v_3 = 11 + 3v_1$:$