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Home » Das Volumen der Kugel beträgt (4/3)πr³ = (4/3)π(4³) = (256/3)π cm³. - AMAZONAWS

Das Volumen der Kugel beträgt (4/3)πr³ = (4/3)π(4³) = (256/3)π cm³. - AMAZONAWS

📅 March 11, 2026 👤 scraface
Mar 11, 2026
Das Volumen der Kugel beträgt (4/3)πr³ = (4/3)π(4³) = (256/3)π cm³.

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