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\boxed(0, 1, 1) - AMAZONAWS
\boxed(0, 1, 1) - AMAZONAWS
📅 March 11, 2026
👤 scraface
Mar 11, 2026
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📌 Thus, $ \boxed{\begin{bmatrix} 1 & -1 \\ 1 & 1 \end{bmatrix}} $.
📌 Actually, $\sin x + \csc x = \sin x + \frac{1}{\sin x} \geq 2$, and similarly for $\cos x + \sec x$. But squaring gives:
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