Bogenlänge = (θ/360) × 2πr = (45/360) × 2π×7 = (1/8) × 14π = (14π)/8 = (7π)/4 ≈ 5,50 cm - AMAZONAWS
📅 March 11, 2026
👤 scraface
Mar 11, 2026
Bogenlänge = (θ/360) × 2πr = (45/360) × 2π×7 = (1/8) × 14π = (14π)/8 = (7π)/4 ≈ 5,50 cm - AMAZONAWS
Mar 11, 2026
