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#### 65.65625 - AMAZONAWS
#### 65.65625 - AMAZONAWS
📅 March 11, 2026
👤 scraface
Mar 11, 2026
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📌 So the solutions are \( z = i\sqrt{2} \) and \( z = -i\sqrt{2} \). Each appears once, but note: quadratic in \( z^2 \) gives two roots, each of multiplicity one. However, since \( z^2 = -2 \) has two complex roots, and no further multiplicity, the full set of roots is \( i\sqrt{2}, -i\sqrt{2} \).
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