Solution: Simplify $ f(n) $ by factoring the numerator: $ n^3 - 8 = (n - 2)(n^2 + 2n + 4) $. Thus, $ f(n) = rac{(n - 2)(n^2 + 2n + 4)}{n - 2} = n^2 + 2n + 4 $ for $ n