The leading coefficient of the numerator $ 3t^2 $ is 3, and of the denominator $ t^2 $ is 1. Thus, the horizontal asymptote is $ y = \frac31 = 3 $. - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$The leading coefficient of the numerator $ 3t^2 $ is 3, and of the denominator $ t^2 $ is 1. Thus, the horizontal asymptote is $ y = \frac{3}{1} = 3 $.$

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