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Home » t = \frac{-b \pm \sqrtb^2 - 4ac}2a = \frac{5 \pm \sqrt25 - 24}2 = \frac5 \pm 12 - AMAZONAWS

t = \frac{-b \pm \sqrtb^2 - 4ac}2a = \frac{5 \pm \sqrt25 - 24}2 = \frac5 \pm 12 - AMAZONAWS

📅 March 11, 2026 👤 scraface
Mar 11, 2026
t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \frac{5 \pm \sqrt{25 - 24}}{2} = \frac{5 \pm 1}{2}

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  • Thus, \( r = \frac{31.4}{2\pi} \approx \frac{31.4}{6.28} = 5 \) cm.
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