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Subtract 36: \( b^2 = 64 \). - AMAZONAWS
Subtract 36: \( b^2 = 64 \). - AMAZONAWS
📅 March 11, 2026
👤 scraface
Mar 11, 2026
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📌 Für $ x = 1 $: $ x \mid y \iff y = k \cdot 1 = k $, also $ y $ ist beliebig teilbar â $ y \mid x $? $ y \mid 1 $ â $ y = \pm1 $. Also $ x \mid y \Rightarrow y = \pm1 $, aber $ (\pm1) \mid 1 $: wahr. Also **ja**, $ x \mid y \Rightarrow y \mid x $ gilt.
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📌 - 34 = 22
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