\[ n = \frac\log(1.8)\log(1.02) \approx 29.25 \] - AMAZONAWS 📅 March 11, 2026 👤 scraface Mar 11, 2026
![\[ n = \frac{\log(1.8)}{\log(1.02)} \approx 29.25 \]](https://soloferat.biz.id/images/-n--fraclog18log102-approx-2925-.jpg)
