z = e^-2\pi i / 9,\ e^-8\pi i / 9,\ e^-14\pi i / 9 = e^4\pi i / 9 \quad \text(since -14\pi/9 \equiv 4\pi/9 \mod 2\pi). - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$z = e^{-2\pi i / 9},\ e^{-8\pi i / 9},\ e^{-14\pi i / 9} = e^{4\pi i / 9} \quad \text{(since } -14\pi/9 \equiv 4\pi/9 \mod 2\pi).$