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Home » Solution: For vectors to be orthogonal, their dot product must be zero: $ 2x + (-1)(3) = 0 $. Solving $ 2x - 3 = 0 $ gives $ x = \frac32 $. The ordered pair is $ \boxed{\left( \frac32, 3 \right)} $. - AMAZONAWS

Solution: For vectors to be orthogonal, their dot product must be zero: $ 2x + (-1)(3) = 0 $. Solving $ 2x - 3 = 0 $ gives $ x = \frac32 $. The ordered pair is $ \boxed{\left( \frac32, 3 \right)} $. - AMAZONAWS

📅 March 11, 2026 👤 scraface
Mar 11, 2026
Solution: For vectors to be orthogonal, their dot product must be zero: $ 2x + (-1)(3) = 0 $. Solving $ 2x - 3 = 0 $ gives $ x = \frac{3}{2} $. The ordered pair is $ \boxed{\left( \frac{3}{2}, 3 \right)} $.

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