f(\theta) = 1 - 6 \cdot \frac14 \sin^2(2\theta) = 1 - \frac32 \sin^2(2\theta). - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$f(\theta) = 1 - 6 \cdot \frac{1}{4} \sin^2(2\theta) = 1 - \frac{3}{2} \sin^2(2\theta).$