\fracx^2y + \fracy^2z + \fracz^2x \geq \frac(x + y + z)^2y + z + x = \frac3^23 = 3 - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$\frac{x^2}{y} + \frac{y^2}{z} + \frac{z^2}{x} \geq \frac{(x + y + z)^2}{y + z + x} = \frac{3^2}{3} = 3$