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A. Hippocampus - AMAZONAWS
A. Hippocampus - AMAZONAWS
📅 March 11, 2026
👤 scraface
Mar 11, 2026
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📌 However, correct interpretation: if parts arrive every 1.25 s and take 8.5 s to process, then at any time, number of active parts = \( \frac{8.5}{1.25} = 6.8 \), but in steady state with continuous flow, the number in process is \( \text{arrival rate} \times \text{service time} = \frac{1}{1.25} \times 8.5 = 6.8 \). Since partial parts aren’t physical, but for modeling, we report as computed.
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📌 Evaluating the integral:
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📌 \( P(20) = 1200 e^{0.1856 \times 20} = 1200 e^{3.712} \)
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