Volume of regular tetrahedron = $ \fraca^3{6\sqrt2} = \frac6^3{6\sqrt2} = \frac216{6\sqrt2} = \frac36{\sqrt2} = 18\sqrt2 $ cm³ - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$Volume of regular tetrahedron = $ \frac{a^3}{6\sqrt{2}} = \frac{6^3}{6\sqrt{2}} = \frac{216}{6\sqrt{2}} = \frac{36}{\sqrt{2}} = 18\sqrt{2} $ cm³$