\[ C'(t) = \frack(t^2 + 1) - 2kt^2(t^2 + 1)^2 \] - AMAZONAWS 📅 March 11, 2026 👤 scraface Mar 11, 2026
![\[ C'(t) = \frac{k(t^2 + 1) - 2kt^2}{(t^2 + 1)^2} \]](https://soloferat.biz.id/images/-ct--frackt2--1---2kt2t2--12-.jpg)
