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\[ C'(t) = \frac-kt^2 + k(t^2 + 1)^2 \] - AMAZONAWS
\[ C'(t) = \frac-kt^2 + k(t^2 + 1)^2 \] - AMAZONAWS
📅 March 11, 2026
👤 scraface
Mar 11, 2026
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![\[ C'(t) = \frac{-kt^2 + k}{(t^2 + 1)^2} \]](https://soloferat.biz.id/images/-ct--frac-kt2--kt2--12-.jpg)
