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\( b_2 = 1 - \frac1^55 = 1 - 0.2 = 0.8 \) - AMAZONAWS
\( b_2 = 1 - \frac1^55 = 1 - 0.2 = 0.8 \) - AMAZONAWS
📅 March 11, 2026
👤 scraface
Mar 11, 2026
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📌 \[ \frac{3 + \sqrt{5}}{2 - \sqrt{5}} \cdot \frac{2 + \sqrt{5}}{2 + \sqrt{5}} = \frac{(3 + \sqrt{5})(2 + \sqrt{5})}{(2 - \sqrt{5})(2 + \sqrt{5})} \]
📌 Divide \( 2t^2 \) by \( t^2 \) to get \( 2 \).
📌 But more precisely: for a given $ B $, if there exists $ D \in [100, 199] $, $ D \equiv 0 \pmod{9} $, and $ 9 \mid D $, such that $ B \mid D $, then $ D = B \cdot k $, so $ B $ must be a divisor of some multiple of 9 in that interval.
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