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Take ln: \( t \ln(1.08) > \ln(1.5625) \) - AMAZONAWS
Take ln: \( t \ln(1.08) > \ln(1.5625) \) - AMAZONAWS
📅 March 11, 2026
👤 scraface
Mar 11, 2026
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📌 C: Neutral output
📌 So: $ 1 = \frac{1}{8} \cdot (1/2)^{t/150} $ → no — that’s not correct.
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